Base | Representation |
---|---|
bin | 11101001000100111000… |
… | …111110100001100010011 |
3 | 21002101210120021212101011 |
4 | 131020213013310030103 |
5 | 230300310421321042 |
6 | 4131431313351351 |
7 | 264435115505215 |
oct | 35104707641423 |
9 | 7071716255334 |
10 | 2002111120147 |
11 | 7020aa594686 |
12 | 284032b68557 |
13 | 116a4ba468a8 |
14 | 6cc8cdd25b5 |
15 | 3712d4dea17 |
hex | 1d2271f4313 |
2002111120147 has 2 divisors, whose sum is σ = 2002111120148. Its totient is φ = 2002111120146.
The previous prime is 2002111120057. The next prime is 2002111120157. The reversal of 2002111120147 is 7410211112002.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2002111120147 - 27 = 2002111120019 is a prime.
It is not a weakly prime, because it can be changed into another prime (2002111120157) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1001055560073 + 1001055560074.
It is an arithmetic number, because the mean of its divisors is an integer number (1001055560074).
Almost surely, 22002111120147 is an apocalyptic number.
2002111120147 is a deficient number, since it is larger than the sum of its proper divisors (1).
2002111120147 is an equidigital number, since it uses as much as digits as its factorization.
2002111120147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 224, while the sum is 22.
Adding to 2002111120147 its reverse (7410211112002), we get a palindrome (9412322232149).
The spelling of 2002111120147 in words is "two trillion, two billion, one hundred eleven million, one hundred twenty thousand, one hundred forty-seven".
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