Base | Representation |
---|---|
bin | 101101100001011101001000… |
… | …110100000100011010010111 |
3 | 222020212222220100010120200111 |
4 | 231201131020310010122113 |
5 | 202220224334230042101 |
6 | 1545451415245023451 |
7 | 60112530150543463 |
oct | 5541351064043227 |
9 | 866788810116614 |
10 | 200211122112151 |
11 | 58880072a36a77 |
12 | 1a55630b854b87 |
13 | 8793a9b8bbab7 |
14 | 37623accc14a3 |
15 | 1822e3db74251 |
hex | b61748d04697 |
200211122112151 has 2 divisors, whose sum is σ = 200211122112152. Its totient is φ = 200211122112150.
The previous prime is 200211122112139. The next prime is 200211122112179. The reversal of 200211122112151 is 151211221112002.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 200211122112151 - 25 = 200211122112119 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (200211122112121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100105561056075 + 100105561056076.
It is an arithmetic number, because the mean of its divisors is an integer number (100105561056076).
Almost surely, 2200211122112151 is an apocalyptic number.
200211122112151 is a deficient number, since it is larger than the sum of its proper divisors (1).
200211122112151 is an equidigital number, since it uses as much as digits as its factorization.
200211122112151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 160, while the sum is 22.
Adding to 200211122112151 its reverse (151211221112002), we get a palindrome (351422343224153).
The spelling of 200211122112151 in words is "two hundred trillion, two hundred eleven billion, one hundred twenty-two million, one hundred twelve thousand, one hundred fifty-one".
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