Base | Representation |
---|---|
bin | 101101100001011101001101… |
… | …010101001110101101101111 |
3 | 222020220000002121202201020011 |
4 | 231201131031111032231233 |
5 | 202220230013131221332 |
6 | 1545451430553434051 |
7 | 60112532061053152 |
oct | 5541351525165557 |
9 | 866800077681204 |
10 | 200211197913967 |
11 | 588801017aaaa9 |
12 | 1a55633110b927 |
13 | 8793ab150c346 |
14 | 37623b8db3c99 |
15 | 1822e45648e47 |
hex | b6174d54eb6f |
200211197913967 has 2 divisors, whose sum is σ = 200211197913968. Its totient is φ = 200211197913966.
The previous prime is 200211197913911. The next prime is 200211197914001. The reversal of 200211197913967 is 769319791112002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 200211197913967 - 247 = 59473709558639 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (200211197923967) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100105598956983 + 100105598956984.
It is an arithmetic number, because the mean of its divisors is an integer number (100105598956984).
Almost surely, 2200211197913967 is an apocalyptic number.
200211197913967 is a deficient number, since it is larger than the sum of its proper divisors (1).
200211197913967 is an equidigital number, since it uses as much as digits as its factorization.
200211197913967 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2571912, while the sum is 58.
The spelling of 200211197913967 in words is "two hundred trillion, two hundred eleven billion, one hundred ninety-seven million, nine hundred thirteen thousand, nine hundred sixty-seven".
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