Base | Representation |
---|---|
bin | 1001000110101100001111… |
… | …10111101111001111000011 |
3 | 2121220000000102102110202122 |
4 | 10203112013313233033003 |
5 | 10111011224224232321 |
6 | 110325324310034455 |
7 | 4134323032644536 |
oct | 443260767571703 |
9 | 77800012373678 |
10 | 20021122102211 |
11 | 6419a0152805a |
12 | 22b4289348a2b |
13 | b22ca32aa579 |
14 | 4d3055596a1d |
15 | 24abde3a18ab |
hex | 123587def3c3 |
20021122102211 has 2 divisors, whose sum is σ = 20021122102212. Its totient is φ = 20021122102210.
The previous prime is 20021122102171. The next prime is 20021122102307. The reversal of 20021122102211 is 11220122112002.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 20021122102211 - 210 = 20021122101187 is a prime.
It is a super-3 number, since 3×200211221022113 (a number of 41 digits) contains 333 as substring.
It is a Sophie Germain prime.
It is a self number, because there is not a number n which added to its sum of digits gives 20021122102211.
It is not a weakly prime, because it can be changed into another prime (20021422102211) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10010561051105 + 10010561051106.
It is an arithmetic number, because the mean of its divisors is an integer number (10010561051106).
Almost surely, 220021122102211 is an apocalyptic number.
20021122102211 is a deficient number, since it is larger than the sum of its proper divisors (1).
20021122102211 is an equidigital number, since it uses as much as digits as its factorization.
20021122102211 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 64, while the sum is 17.
Adding to 20021122102211 its reverse (11220122112002), we get a palindrome (31241244214213).
The spelling of 20021122102211 in words is "twenty trillion, twenty-one billion, one hundred twenty-two million, one hundred two thousand, two hundred eleven".
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