Base | Representation |
---|---|
bin | 11101001000100111001… |
… | …111011011000000100101 |
3 | 21002101210201001011122002 |
4 | 131020213033123000211 |
5 | 230300311424123044 |
6 | 4131431424215045 |
7 | 264435141451511 |
oct | 35104717330045 |
9 | 7071721034562 |
10 | 2002113114149 |
11 | 702100726815 |
12 | 28403376a485 |
13 | 116a4c294385 |
14 | 6cc8d391141 |
15 | 3712d78574e |
hex | 1d2273db025 |
2002113114149 has 2 divisors, whose sum is σ = 2002113114150. Its totient is φ = 2002113114148.
The previous prime is 2002113114137. The next prime is 2002113114269. The reversal of 2002113114149 is 9414113112002.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2002063693249 + 49420900 = 1414943^2 + 7030^2 .
It is a cyclic number.
It is not a de Polignac number, because 2002113114149 - 240 = 902601486373 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2002113114119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1001056557074 + 1001056557075.
It is an arithmetic number, because the mean of its divisors is an integer number (1001056557075).
Almost surely, 22002113114149 is an apocalyptic number.
It is an amenable number.
2002113114149 is a deficient number, since it is larger than the sum of its proper divisors (1).
2002113114149 is an equidigital number, since it uses as much as digits as its factorization.
2002113114149 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 29.
The spelling of 2002113114149 in words is "two trillion, two billion, one hundred thirteen million, one hundred fourteen thousand, one hundred forty-nine".
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