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200211320131312 = 247194115723516217
BaseRepresentation
bin101101100001011101010100…
…100111011100111011110000
3222020220000102010201222220111
4231201131110213130323300
5202220230240423200222
61545451451041151104
760112535103641020
oct5541352447347360
9866800363658814
10200211320131312
1158880164796776
121a55636602b494
138793b009315b9
1437623cb309a80
151822e5123b777
hexb617549dcef0

200211320131312 has 320 divisors, whose sum is σ = 481366750556160. Its totient is φ = 78754830336000.

The previous prime is 200211320131231. The next prime is 200211320131349. The reversal of 200211320131312 is 213131023112002.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 32203844428 + ... + 32203850644.

It is an arithmetic number, because the mean of its divisors is an integer number (1504271095488).

Almost surely, 2200211320131312 is an apocalyptic number.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 200211320131312, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (240683375278080).

200211320131312 is an abundant number, since it is smaller than the sum of its proper divisors (281155430424848).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

200211320131312 is a wasteful number, since it uses less digits than its factorization.

200211320131312 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8800 (or 8794 counting only the distinct ones).

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 200211320131312 its reverse (213131023112002), we get a palindrome (413342343243314).

The spelling of 200211320131312 in words is "two hundred trillion, two hundred eleven billion, three hundred twenty million, one hundred thirty-one thousand, three hundred twelve".