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200211320131349 is a prime number
BaseRepresentation
bin101101100001011101010100…
…100111011100111100010101
3222020220000102010201222221212
4231201131110213130330111
5202220230240423200344
61545451451041151205
760112535103641102
oct5541352447347425
9866800363658855
10200211320131349
11588801647967aa
121a55636602b505
138793b00931617
1437623cb309aa9
151822e5123b79e
hexb617549dcf15

200211320131349 has 2 divisors, whose sum is σ = 200211320131350. Its totient is φ = 200211320131348.

The previous prime is 200211320131231. The next prime is 200211320131373. The reversal of 200211320131349 is 943131023112002.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 173406574202449 + 26804745928900 = 13168393^2 + 5177330^2 .

It is a cyclic number.

It is not a de Polignac number, because 200211320131349 - 220 = 200211319082773 is a prime.

It is a super-2 number, since 2×2002113201313492 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (200211320136349) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100105660065674 + 100105660065675.

It is an arithmetic number, because the mean of its divisors is an integer number (100105660065675).

Almost surely, 2200211320131349 is an apocalyptic number.

It is an amenable number.

200211320131349 is a deficient number, since it is larger than the sum of its proper divisors (1).

200211320131349 is an equidigital number, since it uses as much as digits as its factorization.

200211320131349 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 7776, while the sum is 32.

The spelling of 200211320131349 in words is "two hundred trillion, two hundred eleven billion, three hundred twenty million, one hundred thirty-one thousand, three hundred forty-nine".