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200212110010147 is a prime number
BaseRepresentation
bin101101100001011110000011…
…101100100110011100100011
3222020220002110012000222222011
4231201132003230212130203
5202220233400130311042
61545452101255053351
760112563504541534
oct5541360354463443
9866802405028864
10200212110010147
115888052a6443a4
121a556546671257
138793bc847c721
14376246419c68b
151822e9a764a17
hexb61783b26723

200212110010147 has 2 divisors, whose sum is σ = 200212110010148. Its totient is φ = 200212110010146.

The previous prime is 200212110010079. The next prime is 200212110010271. The reversal of 200212110010147 is 741010011212002.

It is a happy number.

200212110010147 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-200212110010147 is a prime.

It is not a weakly prime, because it can be changed into another prime (200212110019147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100106055005073 + 100106055005074.

It is an arithmetic number, because the mean of its divisors is an integer number (100106055005074).

Almost surely, 2200212110010147 is an apocalyptic number.

200212110010147 is a deficient number, since it is larger than the sum of its proper divisors (1).

200212110010147 is an equidigital number, since it uses as much as digits as its factorization.

200212110010147 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 224, while the sum is 22.

Adding to 200212110010147 its reverse (741010011212002), we get a palindrome (941222121222149).

The spelling of 200212110010147 in words is "two hundred trillion, two hundred twelve billion, one hundred ten million, ten thousand, one hundred forty-seven".