Base | Representation |
---|---|
bin | 1001000110101100011010… |
… | …01011101010000100101111 |
3 | 2121220000020122002121201021 |
4 | 10203112031023222010233 |
5 | 10111011420032210111 |
6 | 110325341211555011 |
7 | 4134325164233233 |
oct | 443261513520457 |
9 | 77800218077637 |
10 | 20021211210031 |
11 | 6419a4785a089 |
12 | 22b42b315ba67 |
13 | b22cb88a93a5 |
14 | 4d30633505c3 |
15 | 24abe7103d71 |
hex | 12358d2ea12f |
20021211210031 has 2 divisors, whose sum is σ = 20021211210032. Its totient is φ = 20021211210030.
The previous prime is 20021211209983. The next prime is 20021211210149. The reversal of 20021211210031 is 13001211212002.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 20021211210031 - 213 = 20021211201839 is a prime.
It is a super-2 number, since 2×200212112100312 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 20021211209987 and 20021211210014.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20021211210731) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10010605605015 + 10010605605016.
It is an arithmetic number, because the mean of its divisors is an integer number (10010605605016).
Almost surely, 220021211210031 is an apocalyptic number.
20021211210031 is a deficient number, since it is larger than the sum of its proper divisors (1).
20021211210031 is an equidigital number, since it uses as much as digits as its factorization.
20021211210031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 20021211210031 its reverse (13001211212002), we get a palindrome (33022422422033).
The spelling of 20021211210031 in words is "twenty trillion, twenty-one billion, two hundred eleven million, two hundred ten thousand, thirty-one".
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