Base | Representation |
---|---|
bin | 101101100001011110001001… |
… | …101010011010011100011111 |
3 | 222020220002201011101002102201 |
4 | 231201132021222122130133 |
5 | 202220234101241144444 |
6 | 1545452115232232331 |
7 | 60112566131356636 |
oct | 5541361152323437 |
9 | 866802634332381 |
10 | 200212210099999 |
11 | 58880581097389 |
12 | 1a55657409b6a7 |
13 | 8793c131250a6 |
14 | 37624735b451d |
15 | 1822ea4435dd4 |
hex | b61789a9a71f |
200212210099999 has 2 divisors, whose sum is σ = 200212210100000. Its totient is φ = 200212210099998.
The previous prime is 200212210099991. The next prime is 200212210100053. The reversal of 200212210099999 is 999990012212002.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 200212210099999 - 23 = 200212210099991 is a prime.
It is a super-2 number, since 2×2002122100999992 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (200212210099991) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100106105049999 + 100106105050000.
It is an arithmetic number, because the mean of its divisors is an integer number (100106105050000).
Almost surely, 2200212210099999 is an apocalyptic number.
200212210099999 is a deficient number, since it is larger than the sum of its proper divisors (1).
200212210099999 is an equidigital number, since it uses as much as digits as its factorization.
200212210099999 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 944784, while the sum is 55.
The spelling of 200212210099999 in words is "two hundred trillion, two hundred twelve billion, two hundred ten million, ninety-nine thousand, nine hundred ninety-nine".
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