Base | Representation |
---|---|
bin | 11101001000100111111… |
… | …101111111101011110001 |
3 | 21002101211120000110000111 |
4 | 131020213331333223301 |
5 | 230300323040313433 |
6 | 4131432542021321 |
7 | 264435350311015 |
oct | 35104775775361 |
9 | 7071746013014 |
10 | 2002125322993 |
11 | 702107605474 |
12 | 284037877841 |
13 | 116a5197a443 |
14 | 6cc90c4c545 |
15 | 3712e897dcd |
hex | 1d227f7faf1 |
2002125322993 has 2 divisors, whose sum is σ = 2002125322994. Its totient is φ = 2002125322992.
The previous prime is 2002125322987. The next prime is 2002125323111. The reversal of 2002125322993 is 3992235212002.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1986681793009 + 15443529984 = 1409497^2 + 124272^2 .
It is a cyclic number.
It is not a de Polignac number, because 2002125322993 - 229 = 2001588452081 is a prime.
It is not a weakly prime, because it can be changed into another prime (2002125322973) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1001062661496 + 1001062661497.
It is an arithmetic number, because the mean of its divisors is an integer number (1001062661497).
Almost surely, 22002125322993 is an apocalyptic number.
It is an amenable number.
2002125322993 is a deficient number, since it is larger than the sum of its proper divisors (1).
2002125322993 is an equidigital number, since it uses as much as digits as its factorization.
2002125322993 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 116640, while the sum is 40.
The spelling of 2002125322993 in words is "two trillion, two billion, one hundred twenty-five million, three hundred twenty-two thousand, nine hundred ninety-three".
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