Base | Representation |
---|---|
bin | 101101100001011111000110… |
… | …000011111000111001011101 |
3 | 222020220012022210002122012122 |
4 | 231201133012003320321131 |
5 | 202220243140143130133 |
6 | 1545452403551112325 |
7 | 60112633214361161 |
oct | 5541370603707135 |
9 | 866805283078178 |
10 | 200213223411293 |
11 | 58880a51082134 |
12 | 1a5567b75126a5 |
13 | 8794045043081 |
14 | 376252bdc8ca1 |
15 | 1823013396498 |
hex | b617c60f8e5d |
200213223411293 has 2 divisors, whose sum is σ = 200213223411294. Its totient is φ = 200213223411292.
The previous prime is 200213223411277. The next prime is 200213223411323. The reversal of 200213223411293 is 392114322312002.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 168344059714009 + 31869163697284 = 12974747^2 + 5645278^2 .
It is a cyclic number.
It is not a de Polignac number, because 200213223411293 - 24 = 200213223411277 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (200213223411203) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100106611705646 + 100106611705647.
It is an arithmetic number, because the mean of its divisors is an integer number (100106611705647).
Almost surely, 2200213223411293 is an apocalyptic number.
It is an amenable number.
200213223411293 is a deficient number, since it is larger than the sum of its proper divisors (1).
200213223411293 is an equidigital number, since it uses as much as digits as its factorization.
200213223411293 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 31104, while the sum is 35.
Adding to 200213223411293 its reverse (392114322312002), we get a palindrome (592327545723295).
The spelling of 200213223411293 in words is "two hundred trillion, two hundred thirteen billion, two hundred twenty-three million, four hundred eleven thousand, two hundred ninety-three".
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