Base | Representation |
---|---|
bin | 101101100001011111110110… |
… | …010001111100111011001011 |
3 | 222020220021102011100201210211 |
4 | 231201133312101330323023 |
5 | 202220301314243413141 |
6 | 1545453020130421551 |
7 | 60112662236611042 |
oct | 5541376621747313 |
9 | 866807364321724 |
10 | 200214032404171 |
11 | 588813267a5495 |
12 | 1a5569a24318b7 |
13 | 8794143824296 |
14 | 37625a7615559 |
15 | 182305e3e7d81 |
hex | b617f647cecb |
200214032404171 has 2 divisors, whose sum is σ = 200214032404172. Its totient is φ = 200214032404170.
The previous prime is 200214032404159. The next prime is 200214032404193. The reversal of 200214032404171 is 171404230412002.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 200214032404171 - 235 = 200179672665803 is a prime.
It is not a weakly prime, because it can be changed into another prime (200214032404121) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100107016202085 + 100107016202086.
It is an arithmetic number, because the mean of its divisors is an integer number (100107016202086).
Almost surely, 2200214032404171 is an apocalyptic number.
200214032404171 is a deficient number, since it is larger than the sum of its proper divisors (1).
200214032404171 is an equidigital number, since it uses as much as digits as its factorization.
200214032404171 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 10752, while the sum is 31.
Adding to 200214032404171 its reverse (171404230412002), we get a palindrome (371618262816173).
The spelling of 200214032404171 in words is "two hundred trillion, two hundred fourteen billion, thirty-two million, four hundred four thousand, one hundred seventy-one".
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