Base | Representation |
---|---|
bin | 101101100001011111110110… |
… | …010001111100111011100001 |
3 | 222020220021102011100201211122 |
4 | 231201133312101330323201 |
5 | 202220301314243413233 |
6 | 1545453020130422025 |
7 | 60112662236611103 |
oct | 5541376621747341 |
9 | 866807364321748 |
10 | 200214032404193 |
11 | 588813267a5505 |
12 | 1a5569a2431915 |
13 | 87941438242b2 |
14 | 37625a7615573 |
15 | 182305e3e7d98 |
hex | b617f647cee1 |
200214032404193 has 2 divisors, whose sum is σ = 200214032404194. Its totient is φ = 200214032404192.
The previous prime is 200214032404171. The next prime is 200214032404213. The reversal of 200214032404193 is 391404230412002.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 158929590865984 + 41284441538209 = 12606728^2 + 6425297^2 .
It is a cyclic number.
It is not a de Polignac number, because 200214032404193 - 238 = 199939154497249 is a prime.
It is not a weakly prime, because it can be changed into another prime (200214032404103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100107016202096 + 100107016202097.
It is an arithmetic number, because the mean of its divisors is an integer number (100107016202097).
Almost surely, 2200214032404193 is an apocalyptic number.
It is an amenable number.
200214032404193 is a deficient number, since it is larger than the sum of its proper divisors (1).
200214032404193 is an equidigital number, since it uses as much as digits as its factorization.
200214032404193 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 41472, while the sum is 35.
Adding to 200214032404193 its reverse (391404230412002), we get a palindrome (591618262816195).
The spelling of 200214032404193 in words is "two hundred trillion, two hundred fourteen billion, thirty-two million, four hundred four thousand, one hundred ninety-three".
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