Base | Representation |
---|---|
bin | 1011101001111000001… |
… | …1000110110010111101 |
3 | 201010210200110102200010 |
4 | 2322132003012302331 |
5 | 11240022322010023 |
6 | 231551351453433 |
7 | 20315432566110 |
oct | 2723603066275 |
9 | 633720412603 |
10 | 200220110013 |
11 | 77a0503a100 |
12 | 32979387279 |
13 | 15b5aac79a1 |
14 | 999541a577 |
15 | 531c952093 |
hex | 2e9e0c6cbd |
200220110013 has 48 divisors (see below), whose sum is σ = 353005237760. Its totient is φ = 98536188960.
The previous prime is 200220110003. The next prime is 200220110029. The reversal of 200220110013 is 310011022002.
It is not a de Polignac number, because 200220110013 - 25 = 200220109981 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (200220110003) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 2025295 + ... + 2121852.
Almost surely, 2200220110013 is an apocalyptic number.
It is an amenable number.
200220110013 is a deficient number, since it is larger than the sum of its proper divisors (152785127747).
200220110013 is a wasteful number, since it uses less digits than its factorization.
200220110013 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4147198 (or 4147187 counting only the distinct ones).
The product of its (nonzero) digits is 24, while the sum is 12.
Adding to 200220110013 its reverse (310011022002), we get a palindrome (510231132015).
The spelling of 200220110013 in words is "two hundred billion, two hundred twenty million, one hundred ten thousand, thirteen".
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