Base | Representation |
---|---|
bin | 101101100001100110010110… |
… | …001011101111111110110111 |
3 | 222020220221102110010102020021 |
4 | 231201212112023233332313 |
5 | 202220410112041201101 |
6 | 1545500132350550011 |
7 | 60113330165214025 |
oct | 5541462613577667 |
9 | 866827373112207 |
10 | 200221010100151 |
11 | 588842874a5787 |
12 | 1a55820b208307 |
13 | 87949b631b181 |
14 | 3762a6a207715 |
15 | 182331bca85a1 |
hex | b619962effb7 |
200221010100151 has 2 divisors, whose sum is σ = 200221010100152. Its totient is φ = 200221010100150.
The previous prime is 200221010100101. The next prime is 200221010100187. The reversal of 200221010100151 is 151001010122002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 200221010100151 - 233 = 200212420165559 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (200221010100101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100110505050075 + 100110505050076.
It is an arithmetic number, because the mean of its divisors is an integer number (100110505050076).
Almost surely, 2200221010100151 is an apocalyptic number.
200221010100151 is a deficient number, since it is larger than the sum of its proper divisors (1).
200221010100151 is an equidigital number, since it uses as much as digits as its factorization.
200221010100151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 40, while the sum is 16.
Adding to 200221010100151 its reverse (151001010122002), we get a palindrome (351222020222153).
The spelling of 200221010100151 in words is "two hundred trillion, two hundred twenty-one billion, ten million, one hundred thousand, one hundred fifty-one".
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