Base | Representation |
---|---|
bin | 101101100001100110011100… |
… | …110111111000001001001011 |
3 | 222020220221201021022100022012 |
4 | 231201212130313320021023 |
5 | 202220410324304044321 |
6 | 1545500151440250135 |
7 | 60113333030160212 |
oct | 5541463467701113 |
9 | 866827637270265 |
10 | 200221122331211 |
11 | 58884334890623 |
12 | 1a55824091094b |
13 | 8794a03654b97 |
14 | 3762a7b0a0079 |
15 | 1823326a7705b |
hex | b6199cdf824b |
200221122331211 has 2 divisors, whose sum is σ = 200221122331212. Its totient is φ = 200221122331210.
The previous prime is 200221122331183. The next prime is 200221122331213. The reversal of 200221122331211 is 112133221122002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 200221122331211 - 26 = 200221122331147 is a prime.
Together with 200221122331213, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (200221122331213) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100110561165605 + 100110561165606.
It is an arithmetic number, because the mean of its divisors is an integer number (100110561165606).
Almost surely, 2200221122331211 is an apocalyptic number.
200221122331211 is a deficient number, since it is larger than the sum of its proper divisors (1).
200221122331211 is an equidigital number, since it uses as much as digits as its factorization.
200221122331211 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 576, while the sum is 23.
Adding to 200221122331211 its reverse (112133221122002), we get a palindrome (312354343453213).
The spelling of 200221122331211 in words is "two hundred trillion, two hundred twenty-one billion, one hundred twenty-two million, three hundred thirty-one thousand, two hundred eleven".
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