Base | Representation |
---|---|
bin | 11101001000101101100… |
… | …111100111111110001101 |
3 | 21002102002011101201210201 |
4 | 131020231213213332031 |
5 | 230301021322400442 |
6 | 4131450205533501 |
7 | 264440611141654 |
oct | 35105547477615 |
9 | 7072064351721 |
10 | 2002220121997 |
11 | 702156074357 |
12 | 284063574291 |
13 | 116a684bc824 |
14 | 6cc9d68819b |
15 | 37137d717b7 |
hex | 1d22d9e7f8d |
2002220121997 has 2 divisors, whose sum is σ = 2002220121998. Its totient is φ = 2002220121996.
The previous prime is 2002220121977. The next prime is 2002220122013. The reversal of 2002220121997 is 7991210222002.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1889247501001 + 112972620996 = 1374499^2 + 336114^2 .
It is a cyclic number.
It is not a de Polignac number, because 2002220121997 - 215 = 2002220089229 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2002220121977) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1001110060998 + 1001110060999.
It is an arithmetic number, because the mean of its divisors is an integer number (1001110060999).
Almost surely, 22002220121997 is an apocalyptic number.
It is an amenable number.
2002220121997 is a deficient number, since it is larger than the sum of its proper divisors (1).
2002220121997 is an equidigital number, since it uses as much as digits as its factorization.
2002220121997 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18144, while the sum is 37.
Adding to 2002220121997 its reverse (7991210222002), we get a palindrome (9993430343999).
The spelling of 2002220121997 in words is "two trillion, two billion, two hundred twenty million, one hundred twenty-one thousand, nine hundred ninety-seven".
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