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20023002321300 = 223252113759926489
BaseRepresentation
bin1001000110101111101111…
…11100001101000110010100
32121220011212110101111110200
410203113313330031012110
510111024102043240200
6110330235033420500
74134420443360046
oct443276774150624
977804773344420
1020023002321300
11641a7868a2530
1222b4712b6a730
13b232129a6644
144d3193191a96
1524ac9e4a3800
hex1235f7f0d194

20023002321300 has 432 divisors, whose sum is σ = 71508870014400. Its totient is φ = 4642816665600.

The previous prime is 20023002321293. The next prime is 20023002321319. The reversal of 20023002321300 is 312320032002.

It is a happy number.

20023002321300 is a `hidden beast` number, since 2 + 0 + 0 + 2 + 300 + 232 + 130 + 0 = 666.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 143 ways as a sum of consecutive naturals, for example, 21148456 + ... + 22074944.

It is an arithmetic number, because the mean of its divisors is an integer number (165529791700).

Almost surely, 220023002321300 is an apocalyptic number.

20023002321300 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 20023002321300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (35754435007200).

20023002321300 is an abundant number, since it is smaller than the sum of its proper divisors (51485867693100).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

20023002321300 is a wasteful number, since it uses less digits than its factorization.

20023002321300 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 926616 (or 926606 counting only the distinct ones).

The product of its (nonzero) digits is 432, while the sum is 18.

Adding to 20023002321300 its reverse (312320032002), we get a palindrome (20335322353302).

It can be divided in two parts, 20023002 and 321300, that added together give a palindrome (20344302).

The spelling of 20023002321300 in words is "twenty trillion, twenty-three billion, two million, three hundred twenty-one thousand, three hundred".