Base | Representation |
---|---|
bin | 1001000110110000001010… |
… | …01111110110111011111101 |
3 | 2121220012110000111002000012 |
4 | 10203120011033312323331 |
5 | 10111030031221432323 |
6 | 110330313130513005 |
7 | 4134426124123655 |
oct | 443300517667375 |
9 | 77805400432005 |
10 | 20023225577213 |
11 | 641a890919a51 |
12 | 22b4775895765 |
13 | b2324a014031 |
14 | 4d31b4aa9365 |
15 | 24acb3da3678 |
hex | 1236053f6efd |
20023225577213 has 2 divisors, whose sum is σ = 20023225577214. Its totient is φ = 20023225577212.
The previous prime is 20023225577143. The next prime is 20023225577351. The reversal of 20023225577213 is 31277552232002.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 18987823680004 + 1035401897209 = 4357502^2 + 1017547^2 .
It is a cyclic number.
It is not a de Polignac number, because 20023225577213 - 216 = 20023225511677 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20023225571213) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10011612788606 + 10011612788607.
It is an arithmetic number, because the mean of its divisors is an integer number (10011612788607).
Almost surely, 220023225577213 is an apocalyptic number.
It is an amenable number.
20023225577213 is a deficient number, since it is larger than the sum of its proper divisors (1).
20023225577213 is an equidigital number, since it uses as much as digits as its factorization.
20023225577213 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 352800, while the sum is 41.
The spelling of 20023225577213 in words is "twenty trillion, twenty-three billion, two hundred twenty-five million, five hundred seventy-seven thousand, two hundred thirteen".
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