Base | Representation |
---|---|
bin | 11101001000111001001… |
… | …000111101111011000010 |
3 | 21002102120122002212212222 |
4 | 131020321020331323002 |
5 | 230301420313141114 |
6 | 4131521312451042 |
7 | 264445446111530 |
oct | 35107110757302 |
9 | 7072518085788 |
10 | 2002413412034 |
11 | 702245193a92 |
12 | 2840b8249a82 |
13 | 116a99567929 |
14 | 6ccbb201150 |
15 | 37149d0298e |
hex | 1d23923dec2 |
2002413412034 has 32 divisors (see below), whose sum is σ = 3557319292800. Its totient is φ = 827128552320.
The previous prime is 2002413411983. The next prime is 2002413412079. The reversal of 2002413412034 is 4302143142002.
It is a junction number, because it is equal to n+sod(n) for n = 2002413411994 and 2002413412012.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4102952 + ... + 4564979.
It is an arithmetic number, because the mean of its divisors is an integer number (111166227900).
Almost surely, 22002413412034 is an apocalyptic number.
2002413412034 is a deficient number, since it is larger than the sum of its proper divisors (1554905880766).
2002413412034 is a wasteful number, since it uses less digits than its factorization.
2002413412034 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8668538.
The product of its (nonzero) digits is 4608, while the sum is 26.
Adding to 2002413412034 its reverse (4302143142002), we get a palindrome (6304556554036).
The spelling of 2002413412034 in words is "two trillion, two billion, four hundred thirteen million, four hundred twelve thousand, thirty-four".
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