Search a number
-
+
2002414213411 is a prime number
BaseRepresentation
bin11101001000111001001…
…100000001100100100011
321002102120200121121011121
4131020321030001210203
5230301421014312121
64131521341553111
7264445455660103
oct35107114014443
97072520547147
102002414213411
11702245691087
122840b8575797
13116a99788611
146ccbb36d203
1537149e10141
hex1d239301923

2002414213411 has 2 divisors, whose sum is σ = 2002414213412. Its totient is φ = 2002414213410.

The previous prime is 2002414213367. The next prime is 2002414213439. The reversal of 2002414213411 is 1143124142002.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2002414213411 - 215 = 2002414180643 is a prime.

It is not a weakly prime, because it can be changed into another prime (2002414273411) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1001207106705 + 1001207106706.

It is an arithmetic number, because the mean of its divisors is an integer number (1001207106706).

Almost surely, 22002414213411 is an apocalyptic number.

2002414213411 is a deficient number, since it is larger than the sum of its proper divisors (1).

2002414213411 is an equidigital number, since it uses as much as digits as its factorization.

2002414213411 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 2002414213411 its reverse (1143124142002), we get a palindrome (3145538355413).

The spelling of 2002414213411 in words is "two trillion, two billion, four hundred fourteen million, two hundred thirteen thousand, four hundred eleven".