Base | Representation |
---|---|
bin | 1011101001111111101… |
… | …0001101110111100101 |
3 | 201010212212012210002102 |
4 | 2322133322031313211 |
5 | 11240103320142432 |
6 | 231554425021445 |
7 | 20316262153352 |
oct | 2723772156745 |
9 | 633785183072 |
10 | 200251334117 |
11 | 77a2072624a |
12 | 32987924885 |
13 | 15b6440aba3 |
14 | 9999627629 |
15 | 532056d962 |
hex | 2e9fe8dde5 |
200251334117 has 2 divisors, whose sum is σ = 200251334118. Its totient is φ = 200251334116.
The previous prime is 200251334099. The next prime is 200251334147. The reversal of 200251334117 is 711433152002.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 184967946241 + 15283387876 = 430079^2 + 123626^2 .
It is a cyclic number.
It is not a de Polignac number, because 200251334117 - 214 = 200251317733 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 200251334117.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (200251334147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100125667058 + 100125667059.
It is an arithmetic number, because the mean of its divisors is an integer number (100125667059).
Almost surely, 2200251334117 is an apocalyptic number.
It is an amenable number.
200251334117 is a deficient number, since it is larger than the sum of its proper divisors (1).
200251334117 is an equidigital number, since it uses as much as digits as its factorization.
200251334117 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5040, while the sum is 29.
Adding to 200251334117 its reverse (711433152002), we get a palindrome (911684486119).
The spelling of 200251334117 in words is "two hundred billion, two hundred fifty-one million, three hundred thirty-four thousand, one hundred seventeen".
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