Base | Representation |
---|---|
bin | 111011101011101… |
… | …0110110100100101 |
3 | 12011120021012112001 |
4 | 1313113112310211 |
5 | 13100132031433 |
6 | 530414525301 |
7 | 100424626321 |
oct | 16727266445 |
9 | 5146235461 |
10 | 2002611493 |
11 | 938470723 |
12 | 47a806831 |
13 | 25bb7cc1c |
14 | 14dd78981 |
15 | bac2b57d |
hex | 775d6d25 |
2002611493 has 2 divisors, whose sum is σ = 2002611494. Its totient is φ = 2002611492.
The previous prime is 2002611473. The next prime is 2002611511. The reversal of 2002611493 is 3941162002.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1805995009 + 196616484 = 42497^2 + 14022^2 .
It is a cyclic number.
It is not a de Polignac number, because 2002611493 - 25 = 2002611461 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2002611433) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1001305746 + 1001305747.
It is an arithmetic number, because the mean of its divisors is an integer number (1001305747).
Almost surely, 22002611493 is an apocalyptic number.
It is an amenable number.
2002611493 is a deficient number, since it is larger than the sum of its proper divisors (1).
2002611493 is an equidigital number, since it uses as much as digits as its factorization.
2002611493 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2592, while the sum is 28.
The square root of 2002611493 is about 44750.5474044732. The cubic root of 2002611493 is about 1260.4691905535.
Adding to 2002611493 its reverse (3941162002), we get a palindrome (5943773495).
The spelling of 2002611493 in words is "two billion, two million, six hundred eleven thousand, four hundred ninety-three".
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