Base | Representation |
---|---|
bin | 10010101001111000… |
… | …110100001000110011 |
3 | 1220200221012010120101 |
4 | 102221320310020303 |
5 | 312010202043212 |
6 | 13111322453231 |
7 | 1306236100612 |
oct | 225170641063 |
9 | 56627163511 |
10 | 20030112307 |
11 | 8549526927 |
12 | 3a70064217 |
13 | 1b729bba7a |
14 | d802c3879 |
15 | 7c3718157 |
hex | 4a9e34233 |
20030112307 has 2 divisors, whose sum is σ = 20030112308. Its totient is φ = 20030112306.
The previous prime is 20030112301. The next prime is 20030112313. The reversal of 20030112307 is 70321103002.
It is a balanced prime because it is at equal distance from previous prime (20030112301) and next prime (20030112313).
It is a cyclic number.
It is not a de Polignac number, because 20030112307 - 215 = 20030079539 is a prime.
It is not a weakly prime, because it can be changed into another prime (20030112301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10015056153 + 10015056154.
It is an arithmetic number, because the mean of its divisors is an integer number (10015056154).
Almost surely, 220030112307 is an apocalyptic number.
20030112307 is a deficient number, since it is larger than the sum of its proper divisors (1).
20030112307 is an equidigital number, since it uses as much as digits as its factorization.
20030112307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 252, while the sum is 19.
Adding to 20030112307 its reverse (70321103002), we get a palindrome (90351215309).
The spelling of 20030112307 in words is "twenty billion, thirty million, one hundred twelve thousand, three hundred seven".
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