Base | Representation |
---|---|
bin | 1001000110111110000101… |
… | …11010001111110000001111 |
3 | 2121220220202002201122111101 |
4 | 10203133002322033300033 |
5 | 10111140334323100111 |
6 | 110333551104203531 |
7 | 4135112324262355 |
oct | 443370272176017 |
9 | 77826662648441 |
10 | 20030702550031 |
11 | 6422a78432328 |
12 | 22b61019095a7 |
13 | b23b6c09bac4 |
14 | 4d36c3b057d5 |
15 | 24b0a04d7bc1 |
hex | 1237c2e8fc0f |
20030702550031 has 2 divisors, whose sum is σ = 20030702550032. Its totient is φ = 20030702550030.
The previous prime is 20030702549983. The next prime is 20030702550043. The reversal of 20030702550031 is 13005520703002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20030702550031 - 215 = 20030702517263 is a prime.
It is a super-2 number, since 2×200307025500312 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20030702550071) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10015351275015 + 10015351275016.
It is an arithmetic number, because the mean of its divisors is an integer number (10015351275016).
Almost surely, 220030702550031 is an apocalyptic number.
20030702550031 is a deficient number, since it is larger than the sum of its proper divisors (1).
20030702550031 is an equidigital number, since it uses as much as digits as its factorization.
20030702550031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6300, while the sum is 28.
The spelling of 20030702550031 in words is "twenty trillion, thirty billion, seven hundred two million, five hundred fifty thousand, thirty-one".
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