Base | Representation |
---|---|
bin | 11101001001100010110… |
… | …010010010100000111101 |
3 | 21002111101022211102111122 |
4 | 131021202302102200331 |
5 | 230304333200011031 |
6 | 4132114512200325 |
7 | 264501662001332 |
oct | 35114262224075 |
9 | 7074338742448 |
10 | 2003112110141 |
11 | 70257362423a |
12 | 2842722390a5 |
13 | 116b7b23c56c |
14 | 6cd45d1a989 |
15 | 3718b31947b |
hex | 1d262c9283d |
2003112110141 has 2 divisors, whose sum is σ = 2003112110142. Its totient is φ = 2003112110140.
The previous prime is 2003112110119. The next prime is 2003112110231. The reversal of 2003112110141 is 1410112113002.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1090867446916 + 912244663225 = 1044446^2 + 955115^2 .
It is a cyclic number.
It is not a de Polignac number, because 2003112110141 - 238 = 1728234203197 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2003112110641) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1001556055070 + 1001556055071.
It is an arithmetic number, because the mean of its divisors is an integer number (1001556055071).
Almost surely, 22003112110141 is an apocalyptic number.
It is an amenable number.
2003112110141 is a deficient number, since it is larger than the sum of its proper divisors (1).
2003112110141 is an equidigital number, since it uses as much as digits as its factorization.
2003112110141 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48, while the sum is 17.
Adding to 2003112110141 its reverse (1410112113002), we get a palindrome (3413224223143).
The spelling of 2003112110141 in words is "two trillion, three billion, one hundred twelve million, one hundred ten thousand, one hundred forty-one".
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