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200311234441 is a prime number
BaseRepresentation
bin1011101010001101111…
…0101101111110001001
3201011001000221000212221
42322203132231332021
511240214134000231
6232004404534041
720320620254023
oct2724336557611
9634030830787
10200311234441
1177a5151924a
12329a39b1321
1315b73951676
1499a357b013
155325951d11
hex2ea37adf89

200311234441 has 2 divisors, whose sum is σ = 200311234442. Its totient is φ = 200311234440.

The previous prime is 200311234433. The next prime is 200311234451. The reversal of 200311234441 is 144432113002.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 149070121216 + 51241113225 = 386096^2 + 226365^2 .

It is a cyclic number.

It is not a de Polignac number, because 200311234441 - 23 = 200311234433 is a prime.

It is not a weakly prime, because it can be changed into another prime (200311234451) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100155617220 + 100155617221.

It is an arithmetic number, because the mean of its divisors is an integer number (100155617221).

Almost surely, 2200311234441 is an apocalyptic number.

It is an amenable number.

200311234441 is a deficient number, since it is larger than the sum of its proper divisors (1).

200311234441 is an equidigital number, since it uses as much as digits as its factorization.

200311234441 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 200311234441 its reverse (144432113002), we get a palindrome (344743347443).

The spelling of 200311234441 in words is "two hundred billion, three hundred eleven million, two hundred thirty-four thousand, four hundred forty-one".