Base | Representation |
---|---|
bin | 1011101010001101111… |
… | …0101101111110001001 |
3 | 201011001000221000212221 |
4 | 2322203132231332021 |
5 | 11240214134000231 |
6 | 232004404534041 |
7 | 20320620254023 |
oct | 2724336557611 |
9 | 634030830787 |
10 | 200311234441 |
11 | 77a5151924a |
12 | 329a39b1321 |
13 | 15b73951676 |
14 | 99a357b013 |
15 | 5325951d11 |
hex | 2ea37adf89 |
200311234441 has 2 divisors, whose sum is σ = 200311234442. Its totient is φ = 200311234440.
The previous prime is 200311234433. The next prime is 200311234451. The reversal of 200311234441 is 144432113002.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 149070121216 + 51241113225 = 386096^2 + 226365^2 .
It is a cyclic number.
It is not a de Polignac number, because 200311234441 - 23 = 200311234433 is a prime.
It is not a weakly prime, because it can be changed into another prime (200311234451) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100155617220 + 100155617221.
It is an arithmetic number, because the mean of its divisors is an integer number (100155617221).
Almost surely, 2200311234441 is an apocalyptic number.
It is an amenable number.
200311234441 is a deficient number, since it is larger than the sum of its proper divisors (1).
200311234441 is an equidigital number, since it uses as much as digits as its factorization.
200311234441 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 200311234441 its reverse (144432113002), we get a palindrome (344743347443).
The spelling of 200311234441 in words is "two hundred billion, three hundred eleven million, two hundred thirty-four thousand, four hundred forty-one".
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