2003113122320 has 80 divisors (see below), whose sum is σ = 4735690771392. Its totient is φ = 787839521280.

The previous prime is 2003113122301. The next prime is 2003113122331. The reversal of 2003113122320 is 232213113002.

It is a tau number, because it is divible by the number of its divisors (80).

It is a Harshad number since it is a multiple of its sum of digits (20).

It is a junction number, because it is equal to n+sod(n) for n = 2003113122292 and 2003113122301.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 686174 + ... + 2115906.

Almost surely, 2^{2003113122320} is an apocalyptic number.

2003113122320 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 2003113122320, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2367845385696).

2003113122320 is an abundant number, since it is smaller than the sum of its proper divisors (2732577649072).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

2003113122320 is a wasteful number, since it uses less digits than its factorization.

2003113122320 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1430040 (or 1430034 counting only the distinct ones).

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 2003113122320 its reverse (232213113002), we get a palindrome (2235326235322).

The spelling of 2003113122320 in words is "two trillion, three billion, one hundred thirteen million, one hundred twenty-two thousand, three hundred twenty".