Base | Representation |
---|---|
bin | 101101100010111011000110… |
… | …001001100010001100110111 |
3 | 222021020122022022212120000102 |
4 | 231202323012021202030313 |
5 | 202223402443314421444 |
6 | 1550010022220104315 |
7 | 60123031215246212 |
oct | 5542730611421467 |
9 | 867218268776012 |
10 | 200312009138999 |
11 | 5890993404350a |
12 | 1a57198669509b |
13 | 87a0459101ca4 |
14 | 376721da82779 |
15 | 1825895bc684e |
hex | b62ec6262337 |
200312009138999 has 2 divisors, whose sum is σ = 200312009139000. Its totient is φ = 200312009138998.
The previous prime is 200312009138993. The next prime is 200312009139007. The reversal of 200312009138999 is 999831900213002.
200312009138999 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 200312009138999 - 212 = 200312009134903 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (200312009138993) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100156004569499 + 100156004569500.
It is an arithmetic number, because the mean of its divisors is an integer number (100156004569500).
Almost surely, 2200312009138999 is an apocalyptic number.
200312009138999 is a deficient number, since it is larger than the sum of its proper divisors (1).
200312009138999 is an equidigital number, since it uses as much as digits as its factorization.
200312009138999 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1889568, while the sum is 56.
The spelling of 200312009138999 in words is "two hundred trillion, three hundred twelve billion, nine million, one hundred thirty-eight thousand, nine hundred ninety-nine".
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