200312013022001 has 2 divisors, whose sum is σ = 200312013022002. Its totient is φ = 200312013022000.

The previous prime is 200312013021979. The next prime is 200312013022003. The reversal of 200312013022001 is 100220310213002.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 193680105610000 + 6631907412001 = 13916900^2 + 2575249^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-200312013022001 is a prime.

Together with 200312013022003, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (200312013022003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100156006511000 + 100156006511001.

It is an arithmetic number, because the mean of its divisors is an integer number (100156006511001).

Almost surely, 2^{200312013022001} is an apocalyptic number.

It is an amenable number.

200312013022001 is a deficient number, since it is larger than the sum of its proper divisors (1).

200312013022001 is an equidigital number, since it uses as much as digits as its factorization.

200312013022001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 200312013022001 its reverse (100220310213002), we get a palindrome (300532323235003).

The spelling of 200312013022001 in words is "two hundred trillion, three hundred twelve billion, thirteen million, twenty-two thousand, one".