Base | Representation |
---|---|
bin | 101101100010111011011001… |
… | …011101011001011110001101 |
3 | 222021020200010220111011002222 |
4 | 231202323121131121132031 |
5 | 202223404124234110404 |
6 | 1550010114312025125 |
7 | 60123042231056411 |
oct | 5542733135313615 |
9 | 867220126434088 |
10 | 200312333113229 |
11 | 58909a8aa02107 |
12 | 1a571a570921a5 |
13 | 87a04ab27510c |
14 | 3767250ad6d41 |
15 | 18258b436ddbe |
hex | b62ed975978d |
200312333113229 has 2 divisors, whose sum is σ = 200312333113230. Its totient is φ = 200312333113228.
The previous prime is 200312333113133. The next prime is 200312333113313. The reversal of 200312333113229 is 922311333213002.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 107743362002500 + 92568971110729 = 10379950^2 + 9621277^2 .
It is a cyclic number.
It is not a de Polignac number, because 200312333113229 - 228 = 200312064677773 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (200312333113829) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100156166556614 + 100156166556615.
It is an arithmetic number, because the mean of its divisors is an integer number (100156166556615).
Almost surely, 2200312333113229 is an apocalyptic number.
It is an amenable number.
200312333113229 is a deficient number, since it is larger than the sum of its proper divisors (1).
200312333113229 is an equidigital number, since it uses as much as digits as its factorization.
200312333113229 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 34992, while the sum is 35.
The spelling of 200312333113229 in words is "two hundred trillion, three hundred twelve billion, three hundred thirty-three million, one hundred thirteen thousand, two hundred twenty-nine".
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