Base | Representation |
---|---|
bin | 11101001001100011111… |
… | …010100000101001111011 |
3 | 21002111102122110021201102 |
4 | 131021203322200221323 |
5 | 230304403021324202 |
6 | 4132120430042015 |
7 | 264502311632444 |
oct | 35114372405173 |
9 | 7074378407642 |
10 | 2003131042427 |
11 | 702583285359 |
12 | 28427864930b |
13 | 116b8213a9b8 |
14 | 6cd486482cb |
15 | 3718cd08d02 |
hex | 1d263ea0a7b |
2003131042427 has 2 divisors, whose sum is σ = 2003131042428. Its totient is φ = 2003131042426.
The previous prime is 2003131042399. The next prime is 2003131042441. The reversal of 2003131042427 is 7242401313002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2003131042427 - 212 = 2003131038331 is a prime.
It is a super-3 number, since 3×20031310424273 (a number of 38 digits) contains 333 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 2003131042427.
It is not a weakly prime, because it can be changed into another prime (2003131042727) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1001565521213 + 1001565521214.
It is an arithmetic number, because the mean of its divisors is an integer number (1001565521214).
Almost surely, 22003131042427 is an apocalyptic number.
2003131042427 is a deficient number, since it is larger than the sum of its proper divisors (1).
2003131042427 is an equidigital number, since it uses as much as digits as its factorization.
2003131042427 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8064, while the sum is 29.
Adding to 2003131042427 its reverse (7242401313002), we get a palindrome (9245532355429).
The spelling of 2003131042427 in words is "two trillion, three billion, one hundred thirty-one million, forty-two thousand, four hundred twenty-seven".
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