Base | Representation |
---|---|
bin | 11101001001100011111… |
… | …010100000101010001001 |
3 | 21002111102122110021201221 |
4 | 131021203322200222021 |
5 | 230304403021324231 |
6 | 4132120430042041 |
7 | 264502311632464 |
oct | 35114372405211 |
9 | 7074378407657 |
10 | 2003131042441 |
11 | 702583285371 |
12 | 284278649321 |
13 | 116b8213a9c9 |
14 | 6cd486482db |
15 | 3718cd08d11 |
hex | 1d263ea0a89 |
2003131042441 has 2 divisors, whose sum is σ = 2003131042442. Its totient is φ = 2003131042440.
The previous prime is 2003131042427. The next prime is 2003131042489. The reversal of 2003131042441 is 1442401313002.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2003085412416 + 45630025 = 1415304^2 + 6755^2 .
It is a cyclic number.
It is not a de Polignac number, because 2003131042441 - 227 = 2002996824713 is a prime.
It is not a weakly prime, because it can be changed into another prime (2003131022441) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1001565521220 + 1001565521221.
It is an arithmetic number, because the mean of its divisors is an integer number (1001565521221).
Almost surely, 22003131042441 is an apocalyptic number.
It is an amenable number.
2003131042441 is a deficient number, since it is larger than the sum of its proper divisors (1).
2003131042441 is an equidigital number, since it uses as much as digits as its factorization.
2003131042441 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 2003131042441 its reverse (1442401313002), we get a palindrome (3445532355443).
The spelling of 2003131042441 in words is "two trillion, three billion, one hundred thirty-one million, forty-two thousand, four hundred forty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.082 sec. • engine limits •