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2003131213319 = 5303377735473
BaseRepresentation
bin11101001001100011111…
…011001010011000000111
321002111102122202222010202
4131021203323022120013
5230304403042311234
64132120433441115
7264502313243615
oct35114373123007
97074378688122
102003131213319
11702583391795
1228427871019b
13116b8219a712
146cd486906b5
153718cd3e77e
hex1d263eca607

2003131213319 has 4 divisors (see below), whose sum is σ = 2003508954096. Its totient is φ = 2002753472544.

The previous prime is 2003131213273. The next prime is 2003131213333. The reversal of 2003131213319 is 9133121313002.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2003131213319 - 28 = 2003131213063 is a prime.

It is a super-2 number, since 2×20031312133192 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2003131213291 and 2003131213300.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2003131213379) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 188862434 + ... + 188873039.

It is an arithmetic number, because the mean of its divisors is an integer number (500877238524).

Almost surely, 22003131213319 is an apocalyptic number.

2003131213319 is a deficient number, since it is larger than the sum of its proper divisors (377740777).

2003131213319 is an equidigital number, since it uses as much as digits as its factorization.

2003131213319 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 377740776.

The product of its (nonzero) digits is 2916, while the sum is 29.

The spelling of 2003131213319 in words is "two trillion, three billion, one hundred thirty-one million, two hundred thirteen thousand, three hundred nineteen".

Divisors: 1 5303 377735473 2003131213319