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2003131213333 is a prime number
BaseRepresentation
bin11101001001100011111…
…011001010011000010101
321002111102122202222011021
4131021203323022120111
5230304403042311313
64132120433441141
7264502313243635
oct35114373123025
97074378688137
102003131213333
117025833917a8
122842787101b1
13116b8219a723
146cd486906c5
153718cd3e78d
hex1d263eca615

2003131213333 has 2 divisors, whose sum is σ = 2003131213334. Its totient is φ = 2003131213332.

The previous prime is 2003131213273. The next prime is 2003131213379. The reversal of 2003131213333 is 3333121313002.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1225309521969 + 777821691364 = 1106937^2 + 881942^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2003131213333 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2003131213298 and 2003131213307.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2003131213933) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1001565606666 + 1001565606667.

It is an arithmetic number, because the mean of its divisors is an integer number (1001565606667).

Almost surely, 22003131213333 is an apocalyptic number.

It is an amenable number.

2003131213333 is a deficient number, since it is larger than the sum of its proper divisors (1).

2003131213333 is an equidigital number, since it uses as much as digits as its factorization.

2003131213333 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2916, while the sum is 25.

Adding to 2003131213333 its reverse (3333121313002), we get a palindrome (5336252526335).

The spelling of 2003131213333 in words is "two trillion, three billion, one hundred thirty-one million, two hundred thirteen thousand, three hundred thirty-three".