Base | Representation |
---|---|
bin | 1001000110111111001110… |
… | …11011111010011110010101 |
3 | 2121220222022210211101121202 |
4 | 10203133213123322132111 |
5 | 10111143113212334131 |
6 | 110334131554522245 |
7 | 4135133445114350 |
oct | 443374733723625 |
9 | 77828283741552 |
10 | 20031315355541 |
11 | 6423262337166 |
12 | 22b6252b96385 |
13 | b23c3902c209 |
14 | 4d3741263297 |
15 | 24b0d91d4bcb |
hex | 1237e76fa795 |
20031315355541 has 32 divisors (see below), whose sum is σ = 24283258997760. Its totient is φ = 16130607353856.
The previous prime is 20031315355531. The next prime is 20031315355577. The reversal of 20031315355541 is 14555351313002.
It is not a de Polignac number, because 20031315355541 - 210 = 20031315354517 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 20031315355495 and 20031315355504.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (20031315355531) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 304500845 + ... + 304566621.
It is an arithmetic number, because the mean of its divisors is an integer number (758851843680).
Almost surely, 220031315355541 is an apocalyptic number.
It is an amenable number.
20031315355541 is a deficient number, since it is larger than the sum of its proper divisors (4251943642219).
20031315355541 is a wasteful number, since it uses less digits than its factorization.
20031315355541 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 70373.
The product of its (nonzero) digits is 135000, while the sum is 38.
Adding to 20031315355541 its reverse (14555351313002), we get a palindrome (34586666668543).
The spelling of 20031315355541 in words is "twenty trillion, thirty-one billion, three hundred fifteen million, three hundred fifty-five thousand, five hundred forty-one".
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