Base | Representation |
---|---|
bin | 1001000110111111001111… |
… | …01110011011101010110101 |
3 | 2121220222100010222000211021 |
4 | 10203133213232123222311 |
5 | 10111143120433210401 |
6 | 110334132250541141 |
7 | 4135133534303524 |
oct | 443374756335265 |
9 | 77828303860737 |
10 | 20031320210101 |
11 | 64232650524a2 |
12 | 22b62547377b1 |
13 | b23c3a03ba35 |
14 | 4d3741b684bb |
15 | 24b0d98432a1 |
hex | 1237e7b9bab5 |
20031320210101 has 2 divisors, whose sum is σ = 20031320210102. Its totient is φ = 20031320210100.
The previous prime is 20031320210023. The next prime is 20031320210113. The reversal of 20031320210101 is 10101202313002.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 17605828564900 + 2425491645201 = 4195930^2 + 1557399^2 .
It is a cyclic number.
It is not a de Polignac number, because 20031320210101 - 213 = 20031320201909 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20031320216101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10015660105050 + 10015660105051.
It is an arithmetic number, because the mean of its divisors is an integer number (10015660105051).
Almost surely, 220031320210101 is an apocalyptic number.
It is an amenable number.
20031320210101 is a deficient number, since it is larger than the sum of its proper divisors (1).
20031320210101 is an equidigital number, since it uses as much as digits as its factorization.
20031320210101 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 16.
Adding to 20031320210101 its reverse (10101202313002), we get a palindrome (30132522523103).
The spelling of 20031320210101 in words is "twenty trillion, thirty-one billion, three hundred twenty million, two hundred ten thousand, one hundred one".
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