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2003331115153 is a prime number
BaseRepresentation
bin11101001001101111110…
…101101110100010010001
321002111221120221000220101
4131021233311232202101
5230310310231141103
64132152334212401
7264510261342034
oct35115765564221
97074846830811
102003331115153
11702676207a15
12284313654101
13116bb471c124
146cd6704901b
15371a0679a1d
hex1d26fd6e891

2003331115153 has 2 divisors, whose sum is σ = 2003331115154. Its totient is φ = 2003331115152.

The previous prime is 2003331115111. The next prime is 2003331115157. The reversal of 2003331115153 is 3515111333002.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2003209961104 + 121154049 = 1415348^2 + 11007^2 .

It is a cyclic number.

It is not a de Polignac number, because 2003331115153 - 233 = 1994741180561 is a prime.

It is not a weakly prime, because it can be changed into another prime (2003331115157) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1001665557576 + 1001665557577.

It is an arithmetic number, because the mean of its divisors is an integer number (1001665557577).

Almost surely, 22003331115153 is an apocalyptic number.

It is an amenable number.

2003331115153 is a deficient number, since it is larger than the sum of its proper divisors (1).

2003331115153 is an equidigital number, since it uses as much as digits as its factorization.

2003331115153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4050, while the sum is 28.

Adding to 2003331115153 its reverse (3515111333002), we get a palindrome (5518442448155).

The spelling of 2003331115153 in words is "two trillion, three billion, three hundred thirty-one million, one hundred fifteen thousand, one hundred fifty-three".