Base | Representation |
---|---|
bin | 1011101010010100110… |
… | …0100100100110110001 |
3 | 201011010001010002121021 |
4 | 2322211030210212301 |
5 | 11240244022010141 |
6 | 232011314055441 |
7 | 20321420113501 |
oct | 2724514444661 |
9 | 634101102537 |
10 | 200340031921 |
11 | 77a667a8217 |
12 | 329b157a581 |
13 | 15b798c51b3 |
14 | 99a7315a01 |
15 | 532823e6d1 |
hex | 2ea53249b1 |
200340031921 has 2 divisors, whose sum is σ = 200340031922. Its totient is φ = 200340031920.
The previous prime is 200340031897. The next prime is 200340031993. The reversal of 200340031921 is 129130043002.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 177489477025 + 22850554896 = 421295^2 + 151164^2 .
It is a cyclic number.
It is not a de Polignac number, because 200340031921 - 25 = 200340031889 is a prime.
It is a super-2 number, since 2×2003400319212 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (200340035921) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100170015960 + 100170015961.
It is an arithmetic number, because the mean of its divisors is an integer number (100170015961).
Almost surely, 2200340031921 is an apocalyptic number.
It is an amenable number.
200340031921 is a deficient number, since it is larger than the sum of its proper divisors (1).
200340031921 is an equidigital number, since it uses as much as digits as its factorization.
200340031921 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 200340031921 its reverse (129130043002), we get a palindrome (329470074923).
The spelling of 200340031921 in words is "two hundred billion, three hundred forty million, thirty-one thousand, nine hundred twenty-one".
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