Base | Representation |
---|---|
bin | 11101001001110100001… |
… | …000110010010101110110 |
3 | 21002112010121121100121221 |
4 | 131021310020302111312 |
5 | 230310432211022332 |
6 | 4132203431500554 |
7 | 264512125254166 |
oct | 35116410622566 |
9 | 7075117540557 |
10 | 2003403220342 |
11 | 702702986687 |
12 | 28433382775a |
13 | 116bc6646c14 |
14 | 6cd728585a6 |
15 | 371a6b6e297 |
hex | 1d274232576 |
2003403220342 has 4 divisors (see below), whose sum is σ = 3005104830516. Its totient is φ = 1001701610170.
The previous prime is 2003403220337. The next prime is 2003403220367. The reversal of 2003403220342 is 2430223043002.
It is a semiprime because it is the product of two primes.
It is a super-3 number, since 3×20034032203423 (a number of 38 digits) contains 333 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500850805084 + ... + 500850805087.
It is an arithmetic number, because the mean of its divisors is an integer number (751276207629).
Almost surely, 22003403220342 is an apocalyptic number.
2003403220342 is a deficient number, since it is larger than the sum of its proper divisors (1001701610174).
2003403220342 is a wasteful number, since it uses less digits than its factorization.
2003403220342 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1001701610173.
The product of its (nonzero) digits is 6912, while the sum is 25.
Adding to 2003403220342 its reverse (2430223043002), we get a palindrome (4433626263344).
The spelling of 2003403220342 in words is "two trillion, three billion, four hundred three million, two hundred twenty thousand, three hundred forty-two".
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