Base | Representation |
---|---|
bin | 101101100011010101100011… |
… | …000011010101111001100010 |
3 | 222021100100121201121222112222 |
4 | 231203111203003111321202 |
5 | 202224334130300424214 |
6 | 1550031040413551042 |
7 | 60125055104063066 |
oct | 5543254303257142 |
9 | 867310551558488 |
10 | 200340411342434 |
11 | 5891a989380310 |
12 | 1a5773924a5482 |
13 | 87a303445321c |
14 | 3768755c0baa6 |
15 | 18264a93d938e |
hex | b635630d5e62 |
200340411342434 has 64 divisors (see below), whose sum is σ = 334928097504000. Its totient is φ = 89101530435840.
The previous prime is 200340411342413. The next prime is 200340411342469. The reversal of 200340411342434 is 434243114043002.
200340411342434 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a junction number, because it is equal to n+sod(n) for n = 200340411342394 and 200340411342403.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 3097424507 + ... + 3097489185.
It is an arithmetic number, because the mean of its divisors is an integer number (5233251523500).
Almost surely, 2200340411342434 is an apocalyptic number.
200340411342434 is a deficient number, since it is larger than the sum of its proper divisors (134587686161566).
200340411342434 is a wasteful number, since it uses less digits than its factorization.
200340411342434 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 71963.
The product of its (nonzero) digits is 110592, while the sum is 35.
Adding to 200340411342434 its reverse (434243114043002), we get a palindrome (634583525385436).
The spelling of 200340411342434 in words is "two hundred trillion, three hundred forty billion, four hundred eleven million, three hundred forty-two thousand, four hundred thirty-four".
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