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200341421141 is a prime number
BaseRepresentation
bin1011101010010101000…
…1110111110001010101
3201011010010201200020212
42322211101313301111
511240244400434031
6232011403535205
720321434660631
oct2724521676125
9634103650225
10200341421141
1177a67566a34
12329b1b2a505
1315b79c90614
1499a7597dc1
15532841612b
hex2ea5477c55

200341421141 has 2 divisors, whose sum is σ = 200341421142. Its totient is φ = 200341421140.

The previous prime is 200341421107. The next prime is 200341421167. The reversal of 200341421141 is 141124143002.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 126786557041 + 73554864100 = 356071^2 + 271210^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-200341421141 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (200341421191) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100170710570 + 100170710571.

It is an arithmetic number, because the mean of its divisors is an integer number (100170710571).

Almost surely, 2200341421141 is an apocalyptic number.

It is an amenable number.

200341421141 is a deficient number, since it is larger than the sum of its proper divisors (1).

200341421141 is an equidigital number, since it uses as much as digits as its factorization.

200341421141 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 768, while the sum is 23.

Adding to 200341421141 its reverse (141124143002), we get a palindrome (341465564143).

The spelling of 200341421141 in words is "two hundred billion, three hundred forty-one million, four hundred twenty-one thousand, one hundred forty-one".