Base | Representation |
---|---|
bin | 1001000111000100111010… |
… | …00011111001001101011001 |
3 | 2121221021012011120222202102 |
4 | 10203202131003321031121 |
5 | 10111220333300342332 |
6 | 110335354210013145 |
7 | 4135302115403144 |
oct | 443423503711531 |
9 | 77837164528672 |
10 | 20034362512217 |
11 | 6424586386069 |
12 | 22b69635771b5 |
13 | b243034148c1 |
14 | 4d394dc2305b |
15 | 24b216991062 |
hex | 12389d0f9359 |
20034362512217 has 2 divisors, whose sum is σ = 20034362512218. Its totient is φ = 20034362512216.
The previous prime is 20034362512147. The next prime is 20034362512259. The reversal of 20034362512217 is 71221526343002.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 18715824740041 + 1318537772176 = 4326179^2 + 1148276^2 .
It is a cyclic number.
It is not a de Polignac number, because 20034362512217 - 218 = 20034362250073 is a prime.
It is not a weakly prime, because it can be changed into another prime (20034362512267) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10017181256108 + 10017181256109.
It is an arithmetic number, because the mean of its divisors is an integer number (10017181256109).
Almost surely, 220034362512217 is an apocalyptic number.
It is an amenable number.
20034362512217 is a deficient number, since it is larger than the sum of its proper divisors (1).
20034362512217 is an equidigital number, since it uses as much as digits as its factorization.
20034362512217 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 120960, while the sum is 38.
Adding to 20034362512217 its reverse (71221526343002), we get a palindrome (91255888855219).
The spelling of 20034362512217 in words is "twenty trillion, thirty-four billion, three hundred sixty-two million, five hundred twelve thousand, two hundred seventeen".
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