Base | Representation |
---|---|
bin | 11101001001110110100… |
… | …110000001110010110011 |
3 | 21002112020111011112200221 |
4 | 131021312212001302303 |
5 | 230311023234041433 |
6 | 4132211503153511 |
7 | 264513135522631 |
oct | 35116646016263 |
9 | 7075214145627 |
10 | 2003444440243 |
11 | 70272417a814 |
12 | 2843455a5897 |
13 | 116c02049aac |
14 | 6cd78108351 |
15 | 371aa5b272d |
hex | 1d276981cb3 |
2003444440243 has 2 divisors, whose sum is σ = 2003444440244. Its totient is φ = 2003444440242.
The previous prime is 2003444440223. The next prime is 2003444440289. The reversal of 2003444440243 is 3420444443002.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2003444440243 - 237 = 1866005486771 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2003444440199 and 2003444440208.
It is not a weakly prime, because it can be changed into another prime (2003444440223) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1001722220121 + 1001722220122.
It is an arithmetic number, because the mean of its divisors is an integer number (1001722220122).
Almost surely, 22003444440243 is an apocalyptic number.
2003444440243 is a deficient number, since it is larger than the sum of its proper divisors (1).
2003444440243 is an equidigital number, since it uses as much as digits as its factorization.
2003444440243 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 147456, while the sum is 34.
Adding to 2003444440243 its reverse (3420444443002), we get a palindrome (5423888883245).
The spelling of 2003444440243 in words is "two trillion, three billion, four hundred forty-four million, four hundred forty thousand, two hundred forty-three".
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