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20035047455201 is a prime number
BaseRepresentation
bin1001000111000110001011…
…11000101111100111100001
32121221022221220102200220002
410203203011320233213201
510111223234122031301
6110335550154425345
74135325103333362
oct443430570574741
977838856380802
1020035047455201
1164248a7a80949
1222b6b14a32255
13b243b22b16cc
144d39b6b9bb69
1524b256b8c16b
hex1238c5e2f9e1

20035047455201 has 2 divisors, whose sum is σ = 20035047455202. Its totient is φ = 20035047455200.

The previous prime is 20035047455191. The next prime is 20035047455209. The reversal of 20035047455201 is 10255474053002.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 15189220102225 + 4845827352976 = 3897335^2 + 2201324^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-20035047455201 is a prime.

It is a super-3 number, since 3×200350474552013 (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (20035047455209) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10017523727600 + 10017523727601.

It is an arithmetic number, because the mean of its divisors is an integer number (10017523727601).

Almost surely, 220035047455201 is an apocalyptic number.

It is an amenable number.

20035047455201 is a deficient number, since it is larger than the sum of its proper divisors (1).

20035047455201 is an equidigital number, since it uses as much as digits as its factorization.

20035047455201 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 168000, while the sum is 38.

The spelling of 20035047455201 in words is "twenty trillion, thirty-five billion, forty-seven million, four hundred fifty-five thousand, two hundred one".