Base | Representation |
---|---|
bin | 1011101010010111101… |
… | …0110000111101111101 |
3 | 201011010212220022101101 |
4 | 2322211322300331331 |
5 | 11240310122004211 |
6 | 232012425413101 |
7 | 20321625046453 |
oct | 2724572607575 |
9 | 634125808341 |
10 | 200352141181 |
11 | 77a72619075 |
12 | 329b563a191 |
13 | 15b7c274b3a |
14 | 99a8b889d3 |
15 | 53293325c1 |
hex | 2ea5eb0f7d |
200352141181 has 2 divisors, whose sum is σ = 200352141182. Its totient is φ = 200352141180.
The previous prime is 200352141169. The next prime is 200352141211. The reversal of 200352141181 is 181141253002.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 199354213081 + 997928100 = 446491^2 + 31590^2 .
It is a cyclic number.
It is not a de Polignac number, because 200352141181 - 29 = 200352140669 is a prime.
It is a super-2 number, since 2×2003521411812 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (200352141131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100176070590 + 100176070591.
It is an arithmetic number, because the mean of its divisors is an integer number (100176070591).
Almost surely, 2200352141181 is an apocalyptic number.
It is an amenable number.
200352141181 is a deficient number, since it is larger than the sum of its proper divisors (1).
200352141181 is an equidigital number, since it uses as much as digits as its factorization.
200352141181 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1920, while the sum is 28.
Adding to 200352141181 its reverse (181141253002), we get a palindrome (381493394183).
The spelling of 200352141181 in words is "two hundred billion, three hundred fifty-two million, one hundred forty-one thousand, one hundred eighty-one".
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