Base | Representation |
---|---|
bin | 101101100011100001110000… |
… | …000010100001011010000111 |
3 | 222021101121102212211201100011 |
4 | 231203201300002201122013 |
5 | 202230042444104230002 |
6 | 1550041044520131051 |
7 | 60126030566005045 |
oct | 5543416002413207 |
9 | 867347385751304 |
10 | 200353514133127 |
11 | 589254a2582953 |
12 | 1a579a2a606a87 |
13 | 87a4341c04a04 |
14 | 376923a093395 |
15 | 18269c48928d7 |
hex | b638700a1687 |
200353514133127 has 2 divisors, whose sum is σ = 200353514133128. Its totient is φ = 200353514133126.
The previous prime is 200353514133119. The next prime is 200353514133131. The reversal of 200353514133127 is 721331415353002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 200353514133127 - 23 = 200353514133119 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 200353514133127.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (200353514133527) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100176757066563 + 100176757066564.
It is an arithmetic number, because the mean of its divisors is an integer number (100176757066564).
Almost surely, 2200353514133127 is an apocalyptic number.
200353514133127 is a deficient number, since it is larger than the sum of its proper divisors (1).
200353514133127 is an equidigital number, since it uses as much as digits as its factorization.
200353514133127 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 226800, while the sum is 40.
Adding to 200353514133127 its reverse (721331415353002), we get a palindrome (921684929486129).
The spelling of 200353514133127 in words is "two hundred trillion, three hundred fifty-three billion, five hundred fourteen million, one hundred thirty-three thousand, one hundred twenty-seven".
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