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200353514134453 is a prime number
BaseRepresentation
bin101101100011100001110000…
…000010100001101110110101
3222021101121102212211210011021
4231203201300002201232311
5202230042444104300303
61550041044520141141
760126030566011651
oct5543416002415665
9867347385753137
10200353514134453
11589254a2583949
121a579a2a6077b1
1387a4341c054b4
14376923a093a61
1518269c4892ebd
hexb638700a1bb5

200353514134453 has 2 divisors, whose sum is σ = 200353514134454. Its totient is φ = 200353514134452.

The previous prime is 200353514134441. The next prime is 200353514134471. The reversal of 200353514134453 is 354431415353002.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 199855702043089 + 497812091364 = 14137033^2 + 705558^2 .

It is a cyclic number.

It is not a de Polignac number, because 200353514134453 - 25 = 200353514134421 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (200353514134493) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100176757067226 + 100176757067227.

It is an arithmetic number, because the mean of its divisors is an integer number (100176757067227).

Almost surely, 2200353514134453 is an apocalyptic number.

It is an amenable number.

200353514134453 is a deficient number, since it is larger than the sum of its proper divisors (1).

200353514134453 is an equidigital number, since it uses as much as digits as its factorization.

200353514134453 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1296000, while the sum is 43.

Adding to 200353514134453 its reverse (354431415353002), we get a palindrome (554784929487455).

The spelling of 200353514134453 in words is "two hundred trillion, three hundred fifty-three billion, five hundred fourteen million, one hundred thirty-four thousand, four hundred fifty-three".