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200353514134691 is a prime number
BaseRepresentation
bin101101100011100001110000…
…000010100001110010100011
3222021101121102212211210111002
4231203201300002201302203
5202230042444104302231
61550041044520142215
760126030566012441
oct5543416002416243
9867347385753432
10200353514134691
11589254a2584045
121a579a2a60796b
1387a4341c05638
14376923a093b91
1518269c48930cb
hexb638700a1ca3

200353514134691 has 2 divisors, whose sum is σ = 200353514134692. Its totient is φ = 200353514134690.

The previous prime is 200353514134651. The next prime is 200353514134699. The reversal of 200353514134691 is 196431415353002.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-200353514134691 is a prime.

It is a super-2 number, since 2×2003535141346912 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (200353514134699) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100176757067345 + 100176757067346.

It is an arithmetic number, because the mean of its divisors is an integer number (100176757067346).

Almost surely, 2200353514134691 is an apocalyptic number.

200353514134691 is a deficient number, since it is larger than the sum of its proper divisors (1).

200353514134691 is an equidigital number, since it uses as much as digits as its factorization.

200353514134691 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1166400, while the sum is 47.

Adding to 200353514134691 its reverse (196431415353002), we get a palindrome (396784929487693).

The spelling of 200353514134691 in words is "two hundred trillion, three hundred fifty-three billion, five hundred fourteen million, one hundred thirty-four thousand, six hundred ninety-one".